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0=4x^2+5x-4
We move all terms to the left:
0-(4x^2+5x-4)=0
We add all the numbers together, and all the variables
-(4x^2+5x-4)=0
We get rid of parentheses
-4x^2-5x+4=0
a = -4; b = -5; c = +4;
Δ = b2-4ac
Δ = -52-4·(-4)·4
Δ = 89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{89}}{2*-4}=\frac{5-\sqrt{89}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{89}}{2*-4}=\frac{5+\sqrt{89}}{-8} $
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